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by siev
546 days ago
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Imagine a function z=f(x,y) in 3D space. Now picture a plane at say, x=3, that is parallel to the plane passing through the Y and Z axes. This x=3 plane cuts through our function, and its intersection with the z=f(x,y) function forms a sort of 2D function z=g(x)=f(3,y). (The Wikipedia page[1] has nice images of this [2]) The slope of this new 2D function on the x=3 plane at some point y is then the partial derivative ∂z/∂y for constant x at the point (3,y). As we are "fixing" the value of x to a constant, by only considering the intersection of our original function with a plane at x=x_0. [1] https://en.wikipedia.org/wiki/Partial_derivative [2] https://en.wikipedia.org/wiki/File:Partial_func_eg.svg |
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Consider f(x,y,z), let’s say f(x, y, z) = x^2 + 3y^3 - e^(-z). What’s the difference between "the partial derivative of f with respect to x" and "the partial derivative of f with respect to x at constant y" ? The first one is already at constant y !
In standard multivariate calculus, the partial derivative of f with respect to x , as you explained, is always "at constant y and z".
In thermodynamics, you can say things like "partial derivative of pressure with respect to volume" and add "at constant temperature" or "at constant entropy" and get different results. What ? Why ? How ?