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by slooonz
546 days ago
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That’s just the standard partial derivative in multivariable calculus. This one I have no trouble to understand. My question is about "at constant something" as used in thermodynamics, where "at constant something" is clearly doing more work than just "partial derivative". What work ? How ? Damned if I know. Consider f(x,y,z), let’s say f(x, y, z) = x^2 + 3y^3 - e^(-z). What’s the difference between "the partial derivative of f with respect to x" and "the partial derivative of f with respect to x at constant y" ? The first one is already at constant y ! In standard multivariate calculus, the partial derivative of f with respect to x , as you explained, is always "at constant y and z". In thermodynamics, you can say things like "partial derivative of pressure with respect to volume" and add "at constant temperature" or "at constant entropy" and get different results. What ? Why ? How ? |
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They're the same thing, isn't it? Except that with add the "at constant temperature" addendum, you're just making explicit the other variable(s) that can potentially be varied. Without it, it just means all other variables, whatever they may be, are constant.
But if something depended on both temperature and some other quantity X, and you said "partial derivative of pressure with respect to volume at constant temperature," that would be sort-of misleading because you're only exlicitly mentioning one of the other two variables - rather, you should say "at constant temperature and X" or not mention either of them.