|
|
|
|
|
by equark
5129 days ago
|
|
It sounds like you're just saying that if you want to know the frequentist properties of an estimator you have to be frequentist. That's a tautology. The harder question is whether there are any decisions you'd prefer to make using a non-Bayesian procedure. That's basically a tautology in the other direction though. |
|
The key here is that Bayesian and frequentist procedures provide different sorts of guarantees. Frequentists optimize for \theta, the possible set of things that could describe all of the data X, while Bayesians will assume a single describing function \theta (this might come from an "expert") and simply optimize the expectation conditioned on the data. Neither is "wrong" but in the case of the bootstrap, the result is calibrated in a way that Bayesian inference simply never will be (if it were, it would be frequentist).
EDIT: As per your second question, actually I think it's not more interesting. A classifier is a type of estimator, so all of the general frequentist guarantees actually still apply to decisionmaking.