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by aw1621107
772 days ago
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> Where Rust won't compile when a lifetime can't be determined, IIRC Nim's static analysis will make a copy (and tell you), so it's more as a performance optimisation than for correctness. Wait, how does that work? For example, take the following Rust function with insufficient lifetime specifiers: pub fn lt(x: &i32, y: &i32) -> &i32 {
if x < y { x } else { y }
}
You're saying Nim will change one/all of those references to copies and will also emit warnings saying it did that? |
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Writing an equivalent program is a bit weird because: 1) Nim does not distinguish between owned and borrowed types in the parameters (except wrt. lent which is bugged and only for optimizations), 2) Nim copies all structures smaller than $THRESHOLD regardless (the threshold is only slightly larger than a pointer but definitely includes all integer types - it's somewhere in the manual) and 3) similarly, not having a way to explicitly return borrows cuts out much of the complexity of lifetimes regardless, since it'll just fall back on reference counting. The TL;DR here though is no, unless I'm mistaken, Nim will fall back on reference counting here (were points 1 and 2 changed).
For clarity as to Nim's memory model: it can be thought of as ownership-optimized reference counting. It's basically the same model as Koka (a research language from Microsoft). If you want to learn more about it, because it is very neat and an exceptionally good tradeoff between performance/ease of use/determinism IMO, I would suggest reading the papers on Perseus as the Nim implementation is not very well-documented. (IIRC the main difference between Koka and Nim's implementation is that Nim frees at the end of scope while Koka frees at the point of last use.)