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by sobellian
1045 days ago
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We must ask ourselves what "at rest" means since there are multiple trajectories that give x(0) = 0, x'(0) = 0 and it seems that some posters believe this cannot fully constrain the particle to be either at rest or in motion at t=0. There are multiple ways to resolve this dissonance. We could demand that the higher derivatives are also zero. We could derive some elaborate rule excluding non-zero x''(t) in the neighborhood of t=0. Or something else altogether. The issue IMO with these resolutions is that they're quite complicated and Newton almost certainly did not have any of them in mind. It's much simpler to just content ourselves that NFL is a special case of F=ma (where F=0). I'm not sure why we should contort ourselves to preserve determinism since we know that gets thrown out the window with QM anyway. |
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