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> ...by the time x.len() gets executed, arg0 already exists... So, I realize that this is the way that Java does it--and, presumably, one still doesn't get fired for doing whatever Java does ;P--but, would it not actually make more sense for the arguments to be evaluated before the target reference, making the argument order more like Haskell/Erlang (but very sadly not Elixir, which makes it awkwardly incompatible with Erlang and breaks some of the basic stuff like fold/reduce)? Particularly so, given that, as far as I can tell from this example, what makes arg0 have the type that it does is the type of the function that hasn't even been called yet? (As in, the semantic gap I am seeing between what the user probably meant and what the compiler wants to do is that "x" shouldn't really be mutably-borrowed until the call happens, and the call here clearly shouldn't happen until after the arguments are evaluated.) (Note: I do not program in Rust currently; I just have spent a number of decades analyzing languages and at times teaching college language design courses. I might be missing something obvious elsewhere that forces Rust to do this, but that one example, in isolation, at least feels like an unforced error.) |