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by MereInterest
1100 days ago
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It does, but Rust also has separate namespaces for methods and variables. That is, a.foo(b) will always be a method foo and never a field foo, because the syntax is that of a method. In order to access a function object, then call it, you would use (a.foo)(b). The parentheses cause the contents to be parsed as a variable expression. |
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