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by npinsker 1614 days ago
Yes, you can -- I believe the EV was around 3.47 for that. The "greedy" strategy (minimizing the worst-case size of the largest set) also ends up using at most 5 words.

Perhaps unsurprisingly, you can't guarantee at most 4 words.

1 comments

You can get EV of 3.46393 with a guaranteed maximum of five tries. (I don't know whether this bound is tight.)
Good to know.

Another possible question is: What is the best strategy minimizing (at any point) _first_ the maximum number of tries, and second the EV (average number of tries over all possible words)? That's subtly different from either answer.