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by Sesse__ 1614 days ago
You can get EV of 3.46393 with a guaranteed maximum of five tries. (I don't know whether this bound is tight.)
1 comments

Good to know.

Another possible question is: What is the best strategy minimizing (at any point) _first_ the maximum number of tries, and second the EV (average number of tries over all possible words)? That's subtly different from either answer.