Kinda like https://what3words.com/. Question is, how long would the string of words have to be to enable such a scheme for the entire IPv6 address space?
8 words. 128 bit address space and 65k English words gives you 16 bits per word, so you need 8 words to cover the entire space.
My dictionary excludes all proper nouns and all words longer than 8 characters. Only about 60% of the 8 character words were used, chosen completely at random. Even so, given a full IPv6 address the resulting "phrase" is a mouthful. Shortened addresses are a little easier to deal with.
Number of IPv6 addresses: ~340 undecillion [1]
Length of string of words: ~8.4 [2]
Probably closer to 8 as what3words likely doesn't cover the full 3-word-address-space of the English language.
[0] https://en.wikipedia.org/wiki/What3words#cite_note-16 [1] https://en.wikipedia.org/wiki/IPv6#cite_ref-rfc2460_2-2 [2] https://www.wolframalpha.com/input/?i=log+base+38485+of+340%...