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by jandrese
2379 days ago
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8 words. 128 bit address space and 65k English words gives you 16 bits per word, so you need 8 words to cover the entire space. My dictionary excludes all proper nouns and all words longer than 8 characters. Only about 60% of the 8 character words were used, chosen completely at random. Even so, given a full IPv6 address the resulting "phrase" is a mouthful. Shortened addresses are a little easier to deal with. |
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