Hacker News new | ask | show | jobs
by kgwgk 2516 days ago
But in this regard the pilot wave is not different from the standard Schroedinger’s wavefunction, is it?
2 comments

No, it isn't. Both are interpretations of non-relativistic quantum mechanics, and in non-relativistic QM there is no speed of light limit.
Schroedinger’s wavefunction isn't sufficient in a relativistic context
True. To be fair, it's true that the relativistic extensions to Bohmian mechanics are not as advanced as for the "standard" theory. But they are not necessarily impossible and the requirement of a prefered foliation may not be so unacceptable if the history of the universe goes back to a singularity (so there is a "local time since singularity" that gives somes sense to the idea of simultaneity).
I am not very familiar with Bohmian mechanics/Pilot wave theory, just wanted to make sure what the schro eq is and isn't was clear to everyone