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by MiroF 2508 days ago
Schroedinger’s wavefunction isn't sufficient in a relativistic context
1 comments

True. To be fair, it's true that the relativistic extensions to Bohmian mechanics are not as advanced as for the "standard" theory. But they are not necessarily impossible and the requirement of a prefered foliation may not be so unacceptable if the history of the universe goes back to a singularity (so there is a "local time since singularity" that gives somes sense to the idea of simultaneity).
I am not very familiar with Bohmian mechanics/Pilot wave theory, just wanted to make sure what the schro eq is and isn't was clear to everyone