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by fa 3970 days ago
FYI: FFTS [1] in many (most?) cases outperforms FFTW, without runtime calibration. It gets there by using a smarter algorithm algorithm. It doesn't have the bells and whistles of more complete libraries—e.g., restricted to power-of-two transforms for now—but hopefully this will change.

[1] http://anthonix.com/ffts/

1 comments

Is that outperforms on all architectures/"runtimes"?