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by throwaway41597
3994 days ago
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1e100000000 would require about 41 MB [0] of storage so that's not as crazy as I thought. No idea what kind of CPU you need for anything other than an addition though. [0]: log(1eN) / log(10) = N ; therefore: bits_required = log2(1e100000000) = 100000000 * log(10) / log(2) = 3.3e8 bits = 41 MB |
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