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by tierack
6039 days ago
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In that case, /([^@]+)@(.+$)/.match("foo@example.com")[0] returns the whole string matched by the expression, and [1] and [2] return the first and second groups. That's why the throwaway is there. To get rid of the throwaway, this is a possibility: username, domain = */([^@]+)@(.+$)/.match("foo@example.com").captures
Of course, your string better match, otherwise you'll get a NoMethodError. |
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