|
|
|
|
|
by digi_owl
4032 days ago
|
|
If i recall correctly, that's because the basic signaling for USB charging is resistance based. Too high a resistance on the wire, and it may heat up (even melt the plastic wrapping) if they try to draw more than the default 500mA USB amount. |
|
Anyway, an interesting thing about USB C (and maybe 3.0, too) is that it can also negotiate 12 or 20 volts and even up to 5 amps. For the same wattage, a higher voltage will heat the cable less.