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by mathistopheles
4054 days ago
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The expectations are not independent though. There can be no more solutions for b=6 than there are for b=5. Given what we already know, we should calculate those sums, not from i=2, but from i=10^2184 or so, because we there are no solutions below that. The theoretical expected number of solutions for b=6 is therefore vanishingly small. |
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