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by nitrogen
4084 days ago
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Assuming the syntax is valid, tacking (console.log("foo")) on the end of lots of things should log foo, even if there's an error elsewhere. The "console.log('foo')" will be evaluated before trying to call the rest as a function, so even "undefined(console.log('foo'))" logs "foo" when tested in the Firefox JS console: undefined(console.log('foo'))
TypeError: undefined is not a function
"foo"
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