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by coldtea
4112 days ago
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>Oh, so it's not because "there already is a nice implementation in EE." Ok That they said "there already is a nice implementation in EE" doesn't automatically mean they also intended it to remain EE-specific forever. It could be also be read as "we won't merge this in the free edition, as we already have a nice implementation in EE we might merge later". |
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