[wz1000]

    (.:) f g = (f .) . g

This can interestingly be generalized(in a way) to get

    (.::) :: (d -> e) -> (a -> b -> c -> d) -> a -> b -> c -> d
    (.::) f g = ((f .) .) . g

and so on.

Since fmap = (.), substitution would get your point free form.