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by foldr 4122 days ago
That's a very bad argument. Indistinguishability doesn't entail identity. One obvious way to show this is to note that only the latter is a transitive relation. In other words, if A = B and B = C, then A = C; but if A is indistinguishable from B and B is indistinguishable from C, it doesn't follow that A is indistinguishable from C.
4 comments

It doesn't? Why? We're talking about indistinguishability in principle, by any possible form of measurement/observation.
Yes, I know. Indistinguishability in that sense is not a transitive relation. Imagine e.g. that we have detectors which can distinguish As from Cs, but no detectors which can distinguish As from Bs or Bs from Cs. There is no contradiction in that scenario. In contrast, there is no consistent scenario in which A = B and B = C but A != C.
Imagine that we have bunch of As, Bs and Cs in one place. Start testing every one against another. You'll quickly discover two groups - An A tests positive with other As and Bs, but tests negative with Cs. A C tests negative with As, but tests positive with Bs and other Cs. B is the one that tests positive with everything.

Here, I distinguished them all. Doesn't that contradict your argument about indistinguishability not being transitive in general?

Yeah, that strategy would work in the scenario I sketched, but it's easy to change it so that you couldn't do that. Just say we have As, Bs, Cs and Ds and that all pairings are indistinguishable except As with Ds.
But at this point I have to ask, how do you define identity? I'm pretty sure that I could use the strategy I outlined above to separate our objects into three groups - As, Ds and the rest. So how do you define that Bs are not Cs, if there is no possible way for telling the difference?
I'd define identity as the smallest relation holding between all things and themselves.

If you want, you can redefine identity in terms of some notion of indistinguishability, but then you'll end up with the odd consequence that identity is not transitive. In other words, you'd have to say that if A is identical to B, B is identical to C, and C is identical to D, it doesn't necessarily follow that A is identical to D.

There are even semi-realistic examples of this, I think. Suppose that two physical quantities X and Y are indistinguishable by any physically possible test if the difference between X and Y < 3. Then i(1, 2), i(2,3), i(3,4), but clearly not i(1,4).

>Indistinguishability doesn't entail identity.

Of course it does, by Voevodsky's Univalence Axiom ;-).

>One obvious way to show this is to note that only the latter is a transitive relation. In other words, if A = B and B = C, then A = C; but if A is indistinguishable from B and B is indistinguishable from C, it doesn't follow that A is indistinguishable from C.

In this case, you seem to be envisioning A, B, and C as points along a spectrum, and talking about ways to classify them as separate from each-other, in which we can classify {A, B}->+1 or {B, C}->+1, but {A, C}->-1 always holds.

That's fine, but when we say indistinguishable in the p-zombie argument, we're talking about a physical isomorphism, which doesn't really allow for the kinds of games you can get away with when classifying sections of spectrum.

>Of course it does, by Voevodsky's Univalence Axiom ;-).

I think this was a joke, right? Just asking because it's hard to tell sometimes on the internet. I didn't see how VUA was particularly relevant but I may be missing something.

It is question-begging in this context to assert that the existence of a physical isomorphism between A and B entails that A and B are identical, since precisely the question at issue in the case of P-zombies is whether or not that's the case.

I took OP to be making an attempt to avoid begging the question by arguing that in general, indistinguishability in a certain very broad sense entails identity, so that without question-beggingly assuming that the existence of a physical isomorphism entails identity, we could non-question-beggingly argue from indistinguishability to identity. In other words, rather than arguing that P-zombies couldn't differ in any way from us because they're physically identical to us (which just begs the question), the argument would be that they couldn't differ in any way from us because they're indistinguishable from us.

This isn't really germane to the p-zombie thought experiment, but:

Indistinguishability does entail identity. If I have a sphere of iron X, and a sphere of iron Y which is atom-for-atom, electron-for-electron, subatomic-particle-for-subatomic-particle identical to sphere X, and I place sphere X in position A, and sphere Y in position B, then they are still distinguishable, because one is in position A and one is in position B.

Basically, I'm not sure what the two of you mean by "the same", but I suspect you're not in agreement on it.

I think we're talking about a sense of indistinguishable/identical for which the two spheres would be indistinguishable/identical, since we're comparing a person to a P-zombie, so it's clear that we're dealing with two different individuals. I think identity in that sense is still transitive on the ordinary understanding. So e.g. if I can show that sphere A has exactly the same physical constitution as sphere B, and that sphere B has exactly the same physical constitution as sphere C, then presumably sphere A must have exactly the same physical constitution as sphere C.
The human and the p-zombie are distinguishable because one is in the zombie universe and one isn't. For the purposes of the experiment, you're not supposed to be able to tell which universe is which by observation of the universe itself (i.e. there is no property of p-zombies that gives them away as p-zombies), but from the outside looking in I guess you have a label for one and a label for the other.

Like I said, it doesn't seem germane to the thought experiment anyway, which doesn't allow for epsilons, at least none that could have a causative effect on anything. Like, if you have universe A with no consciousness, and universe B with orange-flavored consciousness, and universe C with grape-flavored consciousness, and finally universe D with cherry-flavored consciousness, and none of them are distinguishable from the others except for universe A and universe D, then you're violating the terms of the thought experiment because you have two supposedly physically identical universes which are nonetheless distinguishable by dint of their underlying consciousness substrates (or lack thereof).

Anyway you're right, it is a weak argument, but only because it doesn't go far enough in outlining why p-zombies are ridiculous (which, IMO, the argument I presented instead, does).

Identity isn't what we're measuring here, it's "humanness" or "consciousness" -- things that are behaviorally distinguishable. Up to an abstract categorical similarity.

Thus they only need to be indistinguishable up to some feature of similarity that allows them to be classified in the same group. That's why, for example, we don't have to worry about "A is the same as B except that it is 2 meters to the left."

OP was saying that P-zombies are "the same" as us in virtue of being indistinguishable from us. I was just pointing out that this inference doesn't go through, since two non-identical things can be indistinguishable.
Ah, ok.