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by foldr
4122 days ago
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That's a very bad argument. Indistinguishability doesn't entail identity. One obvious way to show this is to note that only the latter is a transitive relation. In other words, if A = B and B = C, then A = C; but if A is indistinguishable from B and B is indistinguishable from C, it doesn't follow that A is indistinguishable from C. |
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