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by BoppreH
4161 days ago
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I was being handwavy with the values (adding a fixed 20 bytes for header), but let's try something more precise: the average packet size was 483 bytes (average data
length = 441 bytes)
So header size is 42 bytes (483 - 441). Assuming the request uses the same headers, we have 483 / (1+42) = 11.23 amplification.My point is: this is important, but not a 440x amplification attack. |
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