|
|
|
|
|
|
by barrkel
4172 days ago
|
|
|
$0 is not the path of the script. $0 is the path passed to the shell used to execute the script. If run via the #! line, it will contain a path of some kind. But if it's passed directly using "bash myscript.sh", then it won't. And yes, dirname is a way out of this. I'd do this: "$(cd "$(dirname "$0")"; pwd)"
if I wanted the path to the script. I would also sanity-check the path by testing for the existence of some files or directories that are expected to exist under it, before trying to delete it all. |
|
|