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ant6n
4189 days ago
If you use a std::List<T>, doesn't it uses nodes like
T data p next p previous p owner
anyway? It shouldn't create a pointer to the data, just like a std::vector<T> isn't an array of pointers to T.
2 comments
desdiv
4189 days ago
Let's say I have a bunch of
Bullet
objects, and each
Bullet
belongs to multiple lists. In that case, std::list<Bullet> doesn't work and I have to use std::list<Bullet*> instead, thus the extra pointer dereference.
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SamReidHughes
4189 days ago
Only without the owner pointer. But intrusive lists don't need an owner pointer either.
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