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by nickharvey
4198 days ago
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The state of an HLL is completely determined by the set of distinct symbols that appear, not the order or the frequency
of those symbols. So, inserting a billion A's and a single B into an HLL will have exactly the same outcome as inserting a bllion B's and a single A, or even just a single A and a single B. Does this address your concern, or did I misunderstand your point? |
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