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by splinterofchaos
4233 days ago
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I did not mean "any rvalue-reference" and bind to "any l- or rvalue", but that you can have an "int &&", "int& &&", "const int& &&", and even "int&& &&". I updated my comment to say "can be made from" instead "can bind to". Your code example does not work because you call "foo" instead of "bar". But consider this one: #include <iostream> using namespace std; template<class T> T bar(T&& i){ return std::forward<T>(i); } int main() { int i=0;
cout << bar<int&&>(6) << endl;
return 0;
}
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In your example, replace bar<int&&>(6) to bar<int&&>(i).
It won't compile because i is not an r value. bar(i) will compile, because the template parameter is a universal reverence that will become an lvalue (not an rvalue) through reference collapsing.