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by danieldyer
4248 days ago
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Roughly speaking, the drag is proportional to cross-sectional area, whereas engine thrust required is proportional to mass, which in turn is proportional to volume. So, you end up running into a square-cube law situation: http://en.wikipedia.org/wiki/Square-cube_law Also, the Reynolds number will be completely different for a model aircraft compared to a full-sized aircraft, so they will behave quite differently aerodynamically. It's also worth pointing out that even the fastest full-size jet aircraft can only just break the sound barrier at sea level (the F-111 did Mach 1.2 at sea level) – going supersonic typically requires flying at a high altitude, which obviously isn't practical or legal for a radio-controlled model aircraft. |
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For low speeds, maybe. For high speeds, you're well into the high Reynolds number turbulent regime. I've worked on R/C aircraft designs and I'm reasonably sure we got decent results with inviscid aerodynamics. At sea level, you're going to see Re in the millions.
Regarding the Square-Cube law, I'm not sure it's that relevant here. It's pretty clear you could put two of those engines in a AMA sized model, so not exceeding 55 lbf. That'd give you a thrust-to-weight ratio of greater than 1.0.