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by tptacek
4299 days ago
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Is it perhaps so simple that... Colin Percival could effectively describe how to do it in an HN comment, perhaps even challenging someone like Thomas Ptacek to code it up and publish it instead of just yakking on HN like he always does I hate him so much? |
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Just turn that around and you get w[i - 4] = w[i] xor Mangle(w[i - 1]). Now start with i = 43 (i.e., w[i] is the last word of the last round key) and count backwards, filling in words of the round keys until you get to w[0]. Then w[0..3] is the AES key.