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by antiform
6169 days ago
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From the real number axioms: Let x \in R. Then we have that x*0 + x*0 = 0*x + 0*x = (0+0)*x = 0*x = x*0
by commutativity of multiplication, distributivity, the existence of a neutral element 0 for addition, and the commutativity of multiplication once again. Thus, we have that x*0 + x*0 = x*0.
For clarity, define A = x*0.
Then we have that A + A = A
A + A + (-A) = A + (-A), by the existence of additive inverses.
A + (A + (-A)) = (A + (-A)), by associativity of addition
A + 0 = 0, by the definition of additive inverses
A = 0, by the definiton of the neutral element 0 of addition
which gives us our desired result. |
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