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by lostlogin
4557 days ago
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Thanks. This is close but off then: The drawing area is evenly divisible by 13 long words (13x32=416). This is exactly the number of registers that were available in the loop above for the MOVEM.L operation (It appears it could have used 14 registers, but I am guessing the extra 32 pixels would have made the drawing area more cramped by reducing the gray whitespace. |
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