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by dded
4565 days ago
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Here's my take: Let n be the number of people needed.
Probability that a person's birthday is not today: 364/365 Prob. that no one's birthday is today: (364/365)^n Prob. that someone's birthday is today: 1 - (364/365)^n Prob. that someone's birthday covers every day: (1 - (364/365)^n)^365 Setting equal to 0.5 and solving, I get n==2284, which is close to metaphyze's brute force number. |
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