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by sillysaurus2
4576 days ago
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Here's one way it might go down in practice. After law enforcement seizes your computer, they'll scan your computer for any encrypted containers, along with any code that looks like it's used for steganography. They'll find DissidentX, since its README mentions "steganography," which is a keyword that their forensics tools will search for. Then they'll use each encoder in your DissidentX folder to scan your computer for any encoded messages. Unless the message is trivially short (<50 bytes) then they'll come up with a list of suspect messages. This list will include any encoded message you've created using DissidentX, along with some false positives. Then, if you're in the UK, they'll have a judge demand you cooperate with them; any plausible deniability you may have had is gone at that point. It's "cooperate or go to jail." Check out http://www.cl.cam.ac.uk/~rja14/Papers/jsac98-limsteg.pdf and related literature. In particular this quote: Shannon provided us with a proof that
such systems are secure regardless of the computational
power of the opponent [43]. [...] Yet we still
have no comparable theory of steganography. The problem is that there's no such thing as perfectly secure stego (undetectable covert messages), even though there is perfectly secure encryption (unbreakable encrypted messages, regardless of the computational power of the adversary, when implemented correctly, and when not defeated via side channel attacks, and when not compelled to cooperate by a judge). |
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More generally, "we do not have a proof" does not mean "we disprove". You also completely ignored my point about the secret, without which the encoder will not work when an attacker tries to run it.