[duked]

I just verified you are right in most cases it won't use int 0x80.

sample C code where you would expect to see int 0x80: #include <stdio.h>

void main(int argc, char argv) { char name[2]; name[0] = "/bin/sh"; name[1] = NULL; execve(name[0], name, NULL); exit(0);

}

when you build it and then use objdump -D: the relevant code is as follows: 8048419: 8d 54 24 18 lea 0x18(%esp),%edx 804841d: 89 54 24 04 mov %edx,0x4(%esp) 8048421: 89 04 24 mov %eax,(%esp) 8048424: e8 eb fe ff ff call 8048314 <execve@plt> 8048429: c7 04 24 00 00 00 00 movl $0x0,(%esp)

But if you use something that executes a payload it uses int 0x80.

Sample C code :

#include <unistd.h>

char shellcode[] = "\x31\xc0\xb0\x46\x31\xdb\x31\xc9\xcd\x80\xeb\x16" "\x5b\x31\xc0\x88\x43\x07\x89\x5b\x08\x89\x43\x0c" "\xb0\x0b\x8d\x4b\x08\x8d\x53\x0c\xcd\x80\xe8\xe5" "\xff\xff\xff\x2f\x62\x69\x6e\x2f\x73\x68\x4e\x41" "\x41\x41\x41\x42\x42\x42\x42";

int main () {

int (func)();

func = (int ()()) shellcode;

(int)(func)(); }

objdump -D will give you that: 0804a040 <shellcode>: 804a040: 31 c0 xor %eax,%eax 804a042: b0 46 mov $0x46,%al 804a044: 31 db xor %ebx,%ebx 804a046: 31 c9 xor %ecx,%ecx 804a048: cd 80 int $0x80 804a04a: eb 16 jmp 804a062 <shellcode+0x22> 804a04c: 5b pop %ebx 804a04d: 31 c0 xor %eax,%eax 804a04f: 88 43 07 mov %al,0x7(%ebx) 804a052: 89 5b 08 mov %ebx,0x8(%ebx) 804a055: 89 43 0c mov %eax,0xc(%ebx) 804a058: b0 0b mov $0xb,%al 804a05a: 8d 4b 08 lea 0x8(%ebx),%ecx 804a05d: 8d 53 0c lea 0xc(%ebx),%edx 804a060: cd 80 int $0x80 804a062: e8 e5 ff ff ff call 804a04c <shellcode+0xc>

I guess you can force it, but in general the compiler will replace it with calls to libs.

[theboss]

Yeah you can force it if you call shellcode as a function but other than that, libc functions, if the elf is dynamically linked, will be mapped in using the procedure linkage table before main runs

but...this is because printf != the write syscall

[rational_indian]

Can you use pastebin or a github gist for the code?