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by CatDancer 6202 days ago
I didn't quite follow, perhaps an example to help me? Is there a specific place where the code would become shorter?
2 comments

Each element of the returned list represents one way that the parser can "succeed". For example, if your parser is for the regexp "a+" and you give the string "aaabc", then the parser can return (("a" . "aabc") ("aa" . "abc") ("aaa" . "bc")] to say that it can interpret "aaabc" in 3 ways. You can transform this into the "longest" parse by filtering this list for the shortest "remaining string".

If your parser returns [] it means it cannot parse the string, so it all fits together. I don't know if I can find the time to rewrite the code to show you explicitly how this could help, but looking at Parsec (in Haskell) will give you a good idea of what I'm talking about

http://legacy.cs.uu.nl/daan/download/parsec/parsec.html

Very interesting! Would you use this for backtracking?
My comment wasn't JSON specific. After all, the JSON spec was designed to support simple parsing logic from the start. My comment was more oriented towards generalization.