[virgi1]

Yes you are. It's O(nlogn) where n is 5 - i.e. it's constant time (you can easily find the median by 4 comparisons to find the smallest of the 5, followed by 3 comparisons for the 2nd smallest, followed by 2 comparisons for the median - a total of 9 comparisons)

[ihateloggingin]

Put otherwise: to sort them all it's O(n/5*(5 log 5)) = O(n).