Nash equilibrium certainly applies to No limit hold 'em. It's a zero-sum game with finite choices over finite time. Could you explain why you think otherwise? Are you just saying it's practically impossible to calculate?
You can calculate Nash equilibrium only when you know the strategies of your opponents. There is no single winning strategy in complete No limit Holdem, so you don't know how your opponent is going to play.
It's theoretically possible to find Nash equilibrium over all possible strategies but that's not winning strategy. You just lose as little as possible. You lose against most/all strategies.
No, you will tie or beat all strategies because your opponents will make huge mistakes like calling when you are almost never bluffing and folding when you are frequently bluffing.
It's theoretically possible to find Nash equilibrium over all possible strategies but that's not winning strategy. You just lose as little as possible. You lose against most/all strategies.
Take for example Kuhn poker (https://en.wikipedia.org/wiki/Kuhn_poker). It's very simple but first player has several optimal strategies.