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by ianstallings
4669 days ago
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I found this artile by Bryce Paradis that elaborates on using a Nash equilibrium for optimal play. He is known for bringing advanced mathematics to the game of limit poker and winning a small fortune because of it. Here is his take: *
Q: What’s a Nash Equilibrium or “game theory optimal” strategy?
– Failed Math, Port Perry, Ontario
A: An equilibrium strategy is one that wins the most money possible against a perfect opponent (this does not mean an opponent who can see your cards, but one who always knows your range whenever you take an action and makes the best choice against that range). In the game “rock, paper, scissors,” the equilibrium strategy is to randomly choose between the three options, choosing each one a third of the time in the long run. Finding equilibriums in poker is much more complicated, but the concept can be useful when you’re playing lots of hands against tough opponents. For example, if your opponent bets half the pot on the river after a particular series of actions, the pot is offering him 2-1 on his bluff. If he were a perfect player, the right thing to do would be to call his bet a third of the time, since if you called more he’d exploit you by never bluffing and if you called less he’d exploit you by always bluffing. In reality, of course, our opponents are never perfect, and so the idea of playing an equilibrium strategy at the table is usually pretty academic.
* http://pokerpromagazine.com/proscorner/bryce-paradis/ |
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You can certainly use Nash equilibrium when you have figured out the strategies your opponents are using. This is what Bryce Paradis is talking about. It can have practical value when playing Heads Up.
But If we are talking game theory and "solving poker", there is no single winning strategy that works against all other strategies and you can't calculate single Nash equilibrium that would be optimal in actual game against specific strategies.