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by nwhitehead
4690 days ago
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Consider the set P of programs that take no input and generate an infinite stream of digits. Each program in P has a finite length and is written out of a finite set of symbols, so there must only be a finite number of programs of any given length. That makes P countable. Let Q be the set of numbers described by programs in P. Each program from P describes exactly one number, so Q must also be countable. The set of irrational numbers is uncountable, so there must be an uncountable set of "complex" irrational numbers remaining after you take away all the "non complex" ones in Q. |
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But we're surely not talking about a finite number of programs.
I'm not even sure what the Kolmogorov complexity of a "complex irrational number" means. If you need the sequence of digits and you cannot use an algorithm to produce the digits, then the complexity is infinite?