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by acomar
4807 days ago
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But you're quite clearly NOT overloading "=" or ";". Instead of saying do
a = getFoo x y z
b = getBar p q
(which won't compile), you're saying do
a <- getFoo x y z
b <- getBar p q
Which is not an overloaded operator. In fact, it's not even meant to suggest equals (which in Haskell rather strictly means mathematical equality) but rather assignment ("=" in the expression "x = x + 1;"). |
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