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by trhtrsh
4847 days ago
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Proof by contradiction is almost never necessary. Proof that if a number has a rational number square root, it must be a square: Let's suppose that sqrt(p) = a/b
That means that p = (a^2)/(b^2)
That means that p * b^2 = a^2
Therefore p is a square (by counting prime factors). |
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