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by coutud
4855 days ago
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Nope, there's an even simpler way. Say f(x) is the expected value of the number of draws to get to value x.
Then f(x) = 1 + integral_0^x f(x) Hence f'(x) = f(x), so f(x) = c exp(x)
The constant is of course 1, and f(1) = exp(1). |
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