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by ksmiley
4871 days ago
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A roughly spherical asteroid of radius r has volume 4/3 * pi * r^3 Using Ceres as a benchmark for typical asteroid density, an asteroid of radius r has mass [volume in meters^3] * 2077 kg/(m^3) On the asteroid's surface, acceleration due to gravity is [Gravitational constant] * [mass in kilograms] / (r in meters)^2 which simplifies to (6.67384E-11 * 4/3 * pi * 2077 * r) m s^-2 If we mine on a 1km diameter asteroid, the dust we kick up will accelerate towards the surface at 2.9 * 10^-4 m/s^2. A dust cloud 10 meters high will settle in about five minutes. |
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