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by marshray 4901 days ago
You have a magic allocator for your list nodes that does better than O(1) amortized?
2 comments

Being better than O(n) worst case is the target here, not O(1) amortized. For example, O(1) amortized and O(log n) worst case is a thing.
Do you need magic to create an O(1) allocator for a pool of fixed size objects?
Yes, when (as in the general case of std::list) the number of objects is not known in advance.
true. however, libstdc++ implements __pool_alloc for a reason.