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by inigyou 6 days ago
I suppose by default it will just call free, but you can substitute different malloc implementations, maybe one with a malloc_no_header function
1 comments

Because free still exists and there is no “allocate this number of bytes of memory; I promise to free it with a call to free_size” call, you can’t have a malloc implementation that doesn’t track block sizes.

I think the only thing free_size adds is robustness. Allocators can check the passed in size with what they know and abort the program if they do not match. That can thwart some security issues.