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by tapirl 6 days ago
Maybe I'm wrong, but should it be @clz instead?
1 comments
wrs 6 days ago
No, the diagram looks like a binary literal but it's actually backwards from that. Lane 0 becomes the LSB, but that's on the left of the diagram.
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tapirl 6 days ago
Aha, you are right. Smaller indexes are for least-significant bits.
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