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by account42
1 day ago
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> and the latter is a whole damn enum class with a strange adversion to arithmetic, where `byte |= 1` becomes `byte |= std::byte(1)`, `byte += 1` becomes `byte = std::byte(std::to_integer<std::uint8_t>(byte) + 1);`, and both become something you can accidentally step into in your full debug builds because it's an actual function call (at least on MSVC - still extra instructions on clang/gcc, but I can see the dang call instruction on MSVC!) instead of a compiler built in. That's the point, std::byte is for opaque bytes. You're not expected to do arithmetic directly just like you can't do arithmetic on void. |
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That'd make a whole lot more sense to me if `std::byte` didn't explicitly implement a whole bunch of bit twiddling operations:
This isn't opaque. This is a poor man's half-assed `std::bitset<8>` with a guaranteed `sizeof(std::byte) == 1`.