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by atq2119
28 days ago
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If the inputs are constant, then all the multiplies are constant and the only thing that toggles is the accumulation. Which explains the pi situation. Normal vs uniform is less clear, but also not as much of a difference. The arguments about signs isn't just about a signs bit, though. The way you negate during accumulation is that you flip all the bits. Only the final float representation is sign+magnitude, the accumulation itself has two's complement steps. I don't actually know the analysis here, just pointing out that it's not that simple. |
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