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by
uecker
29 days ago
Maybe, but also irrelevant to the discussion because whether you write mat[b * A + a] by hand or mat[b][a] and let the compiler frontend expand then makes no difference to the optimizer.
1 comments
fooker
29 days ago
You missed the point.
Those two representations are equivalent, yes. But that's not what flattening loops mean.
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uecker
29 days ago
You are telling me what my point was?
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Those two representations are equivalent, yes. But that's not what flattening loops mean.