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by fluffybucktsnek
23 days ago
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Not necessarily. In pure theory, yes. But in pure theory, monomorphized code can be deduplicated too. Monomorphization often forces types information to flow, whereas type-erasure considers that a bonus. As such, a compiler may accidentally introduce opaque boundaries that hide type information. Even in cases where this is the programmer's fault and the type info is truly lost, in monomorphisation, that becomes an explicit error, while, for devirtualization, since it's just an optimization, the call is silently revirtualized (until someone notices it while profiling/decompiling). One has explicit intent, the other doesn't. |
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I agree that monomorphization has explicit rules that force specialization, I do not think this is an advantage at all because it is too rigid and one can introduce explicitness at the language level also for devirtualization where this is needed. In this sense, monomorphization is premature optimization which limits what can be expressed at the language level and makes the job of the optimizer much harder (and practically impossible to undo the damage completely).